Question

What force acting on a mass of 15 kg for 1minute can change its velocity from 10 m/s to50 m/s?

Answer 1

Answer:

10newton is the required answer.

Explanation:

Given:-

• Mass of body ,m = 15kg
• Time taken ,t = 1min = 60s
• Initial velocity ,u = 10m/s
• Final velocity ,v = 50m/s

To Find:-

• Force acting ,F

Solution:-

It is given that the mass of the body is 15kg for 1min can change its velocity from 10m/s to 50m/s.

We have to calculate the force acting on the body.

Firstly we calculate the acceleration of the body .

As we know acceleration is defined as the rate of change in velocity.

• a = v-u/t

substitute the value we get

→ a = 50-10/60

→ a = 40/60

→ a = 2/3 ms⁻²

Since the acceleration of the body is 2/3 m/s².

So we can easily calculate the force acting on the body.

• F = ma

Putting the value we get

→ F = 15 × 2/3

→ F = 5×2

→ F = 10N

• Hence, the force acting on the mass is 10 Newton.

Answer 2

To find :

the force acting on the mass

Required Answer :

let's find acceleration of body

Using Formula , a = v - u/t

$\tt↦a \: = \frac{50 - 10}{60} \\ \\ \tt↦a = \frac{40}{60} \\ \\ \tt↦a = \frac{2}{3} {ms}^{ - 2}$

Hence the acceleration of the body is $\tt 2/3ms^{-2}$

Now , F = ma

$\tt↦f \: = \frac{2}{3} \times 15 \\ \\ \tt↦f = 2 \times 5 \\ \\ \tt \pink{↦f = 10n}$

Hence , the force acting on the mass is 10n.

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Key words :

A = Acceleration

v = final velocity

u =initial velocity

t = time

f = force

ma = mechanical advantage

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