What force is acted upon the seawater by the moon if it is 300000 km away from the Earth(mass of the earth is 6*10^24 kg) ?
Answers
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Question :-What force is acted upon the seawater by the moon if it is 300000 km away from the Earth(mass of the earth is 6*10^24 kg) ?
What force is acted upon the seawater by the moon if it is 300000 km away from the Earth(mass of the earth is 6*10^24 kg) ?
Answer :-
Mass of the Earth m1=6×1024kg
Mass of the Earth m1=6×1024kgMass of the Moon m2=7.4×1022kg
Mass of the Earth m1=6×1024kgMass of the Moon m2=7.4×1022kgDistance between the Earth and the Moon d=3.84×105km=3.84×108m
Mass of the Earth m1=6×1024kgMass of the Moon m2=7.4×1022kgDistance between the Earth and the Moon d=3.84×105km=3.84×108m Gravitational Constant G=6.7×10−11Nm2/kg2
Mass of the Earth m1=6×1024kgMass of the Moon m2=7.4×1022kgDistance between the Earth and the Moon d=3.84×105km=3.84×108m Gravitational Constant G=6.7×10−11Nm2/kg2Now, by using Newton’s law of gravitation
Mass of the Earth m1=6×1024kgMass of the Moon m2=7.4×1022kgDistance between the Earth and the Moon d=3.84×105km=3.84×108m Gravitational Constant G=6.7×10−11Nm2/kg2Now, by using Newton’s law of gravitation
F= Gm 1 m 2 / r^2
F=(3.84×108)26.7×10−11×6×1024×7.4×1022
F=(3.84×108)26.7×10−11×6×1024×7.4×1022 F=14.8225×1016297.48×1035
F=20.069×1019
F=20.069×1019 F=20.1×1019N
Hence, the gravitational force of attraction is 20.1×1019N