Question

what force is applied on a piston of area of cross section 2 centimetre square to obtain a force of 150 Newton on the piston of area of cross section 12 CM square in a hydraulic machine.

Answer 1

In a hydraulic machine,a force of 2 N is applied on the piston of area of cross section 10 cm2.What force is obtained on its piston of area of cross section 100 cm2

Answer 2

Concept:

• Hydraulic forces
• Pressure
• The pressure on both sides of the hydraulic machine have to be the same.
• F1/ A1 = F2/ A2

Given:

• Force 1 F1 = 150N
• First area of cross-section A1 = 12 cm^2
• Second area of cross-section A2 = 2 cm^2

Find:

• The force applied on the piston with the area of cross-section of 2 cm^2, F2

Solution:

The pressure on both sides of the hydraulic machines has to be the same.

F1/ A1 = F2/ A2

F1 A2 = F2 A1

F2 = F1 A2/A1

150 x 2 = F2 x 12

6 * F2 = 150

F2 = 150/ 6 = 25 N

The force applied is 25N.

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