Question

what force is required to stretch A copper by 10 metre square in cross section 288 its length why for copper is 1.26 ×10 to the power 12 dyne per cm^2guys answer it fast..​

Answer 1

Answer:

formula put

=AY(dL/L)

Explanation:

=1.26*10*12*10/288

=5.25

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Answer 2

Answer:

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