what force is required to stretch a copper wire 1cm² in cross section to double its length? young's modulus (Y) for copper is 1.26 × 10¹² Dyne/cm².
Please answer me with the solution.
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Answer: Given that,
Young modulus Y=1.26×10
12
dyne/cm
Area A=1cm
2
As the length of the wire is doubled, the change in length is equal to its
original length.
If L is the original length
Then, Δl=l
We know that,
Y=
A×ΔL
F×L
F=Y×A
F=0.126×10
12
×1×10
−4
F=1.2×10
7
N
Hence, the force is 1.2×10
7
N
Explanation:
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