What force is required to stretch a steel wire 1 sq.cm in cross section to double its length?
Ysteel = 2 x 1011Nm-2.
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Answer:
=2x10^7 N
Explanation:
Young's modulus Y=(F/A)/(ΔL/L)
As the length of the wire is doubled, the change in length is equal to its original length.
If Lis the original length, then ΔL=L.
ThereforeY=F/A
F=YxA=2x10^11(N/m2)x(10−2m)2 .
=2x10^7 N
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