What force must act on an area of 1 mm^2 so that the pressure exerted is 20 Nm^2?
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We know, P = F/a [where F = force, P = pressure & a = area]
Given, a = 1mm^2 = 0.0000001 m^2
& P = 20 Nm^-2
Thus, F = Pa = (20 × 0.0000001) N = 0.0000002 N = 2 × 10^(-7) N
HOPE THIS COULD HELP!!!
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