Physics, asked by singhsantosh3978, 10 months ago

What force must act on an area of 1 mm^2 so that the pressure exerted is 20 Nm^2?​

Answers

Answered by antareepray2
3

We know, P = F/a [where F = force, P = pressure & a = area]

Given, a = 1mm^2 = 0.0000001 m^2

& P = 20 Nm^-2

Thus, F = Pa = (20 × 0.0000001) N = 0.0000002 N = 2 × 10^(-7) N

HOPE THIS COULD HELP!!!

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