Question

What force must the brakes apply to a 2800 kg
truck going 30 meters per second to bring it to
rest in 8.0 seconds
​

Answer 1

Answer:

10500 N

Explanation:

Force=m(v-u)/t

Force=2800(0-30)/8.0

Force=2800×-30/8.0

Force =10500N

Answer 2

Answer:10500N

Explanation:

Here, initial velocity (u)=30m/s, final velocity (v)=0, time(t)= 8sec

We know, acceleration (a)= (v-u)/t

=( 0-30)/8

= - 15/4 m/s2

F=ma= -2800×15/4 = -10500N