Question

What force on smaller piston of area 25 cm2 will balance weight of 2000 N on larger piston of area a 100 cm2 ?

Answer 1

Force on the narrow piston = 500 N

Explanation:

In a hydraulic machine, we know that the pressure is equal at both the pistons.

So pressure at narrow piston = pressure at wider piston

P1 = P2

Pressure = Force / Area, so we can write it as:

F1 / A1 = F2 / A2

F1 / 25  = 2000 / 100

F1 = 25 * 20

F1 = 500 N  

Force on the narrow piston = 500 N