What force on smaller piston of area 25 cm² will balance weight of 2000 N on larger piston of area a 100 cm² ?
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In a hydraulic machine,a force of 2 N is applied on the piston of area of cross section 10 cm2.What force is obtained on its piston of area of cross section 100 cm2
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Force on the smaller piston = 480 N
Explanation:
Pressure = Force / area
In a piston, we know that Force (smaller piston) / area of smaller piston = Force larger piston) / area of larger piston
Area of smaller piston, A1 = 24 sq. cm
Area of larger piston, A2 = 100 sq. cm
Force of larger piston, F2 = 2000 N
We know that F1 / A1 = F2 /A2
F1 = F2 * A1 / A2
= 2000 * 24 / 100
Force on the smaller piston = 480 N
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