Question

what force should be applied on body of mass 100kg to displace it from rest by 100m in 10 seconds.​

Answer 1

$\Huge{\underline{\underline{\mathfrak{Answer \colon}}}}$

From the Question,

• Mass of the Object,m = 100 Kg

• Time taken,t = 10s

• Distance Covered,s = 100 m

As,the object starts from rest

• Initial Velocity,u = 0 m/s

Using the Relation,

$\huge{ \boxed{ \boxed{ \green{ \sf{s = ut + \frac{1}{2}at {}^{2} }}}}}$

Putting the values,we get :

$\implies \: \sf{100 = (0)(t) + \frac{1}{2}a(10) {}^{2} } \\ \\ \implies \: \sf{ \cancel{100} = \frac{ \cancel{100}a}{2} } \\ \\ \implies \: \huge{ \mathtt{a = 2ms {}^{ - 2} }}$

We Know that,

$\huge{ \boxed{ \boxed{ \green{ \sf{F = ma }}}}}$

Putting the values,we get:

$\rightarrow \: \sf{F = (100)(2)} \\ \\ \huge{ \rightarrow \: \sf{F= 200 \: N}}$

Thus,the force exerted on the object is 200 N

Answer 2

$\huge{\star}{\underline{\boxed{\red{\sf{Answer :}}}}}{\star}$

We are Given that,

Mass of body (m) = 100 kg

Time (t) = 10 s

Distance (s) = 100 m

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We have formula :-

$\huge{\boxed{\boxed{\sf{S \: = \: ut \: + \: \frac{1}{2}at^2}}}}$

___________[Put Values]

100 = (0)(10) + ½ × a(10)²

100 = 0 + ½ × 10a

100 = 5a

a = 100/5

a = 20

Acceleration (a) = 20 m\s²

=============================

Now Calculate force :-

$\huge{\boxed{\boxed{\sf{F \: = \: ma}}}}$

______________[Put Values]

F = (100)(20)

F = 200

Force (F) = 200 N

∴ Force is 200 N