What force will be required to stretch a steel wire 1 sq cm cross-section to double its length? (y for steel is 2×10^12 n/m^2
Answers
Answered by
2
Hope this answer helped you
Explanation:
Given that,
Young modulus Y=1.26×10
12
dyne/cm
Area A=1cm
2
As the length of the wire is doubled, the change in length is equal to its
original length.
If L is the original length
Then, Δl=l
We know that,
Y=
A×ΔL
F×L
F=Y×A
F=0.126×10
12
×1×10
−4
F=1.2×10
7
N
Hence, the force is 1.2×10
7
N
Similar questions