what force will produce a moment of force of 80 nm if the minimum distance between point of action of force and turning force is 45 cm answer should be (7.7 N)
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F=525N
τ=420N−m
Moment of force
=Force× Perpendicular distance
∴420N−m=525N× Perpendicular distance.
∴ Perpendicular distance
=
525
420
=0.8m
0.8 m is the shortest distance between the point of application of force and the turning point.
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