what force would be required to accelerate a body of mass 20 kg from 1.5 m/s to 9 m/s in one third of a minute?
Answers
Answered by
22
Answer:
7.5N
Explanation:
F=ma
F=20×(9-1.5)÷20
F=7.5N
Answered by
14
Answer:
Answer: 7.5N.
Explanation:
Now, F=ma
F=20×[9-1.5]÷20
F= 20×7.5÷20
F= 20×0.375
F=7.5N
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