Question

What force would be required to stretch a wire 3x10-4 m2 cross-section, so that its length becomes 2.5 times its original length ? Given that is Young's modulus of the material of the wire .6 x 1012 dyne cm-2.​

Answer 1

Answer:

The force 2.7 × 10¹² dyne would be required to stretch a wire.

Explanation:

Given, the cross section area of the wire, A = 3 × 10⁻⁴m² = 3.4cm²

The Young's modulus of the material wire, Y = 0.6 × 10¹²dyne/cm²

Consider that 'L' is the length of the wire, after stretching it becomes L'

Given, L' = 2.5L

ΔL = L' - L = 2.5L - L = 1.5L

Young’s modulus or modulus of elasticity, is the measure of the tensile stiffness of the material or wire. It measures the stiffness of the material on applying the force on it, which causes due to compression or expansion.

$Y = \frac{F \times L}{A \times \triangle L}$

$F=\frac{Y \timesA \times A \times \triangle L}{L}$

$F=\frac{(0.6\times 10^{12}\times 2\times 10^{-4}\times 10^{4}\times1.5L)}{L}$

$F= 2.7\times10^{12}\;dyne$

Therefore, the force required to stretch wire is equal to 2.7 × 10¹² dyne.

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Answer 2

Answer:

What force would be required to stretch a wire 3x10-4 m2 cross-section, so that its length becomes 2.5 times its original length ? Given that is Young's modulus of the material of the wire .6 x 1012 dyne cm-2.