Question

What fraction must be added to 1/3 and 3/5 in order for the 3 fractions to have an average of 6/5 ?

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

To find the average add up the values and divide the sum by the number of values.

Rewriting all values as fractions, rewriting any negatives if necessary and, setting up as an addition problem\[ = \frac{1}{1}+ \frac{1}{2}+ \frac{3}{4}+ \frac{9}{12}+ \frac{29}{8}+ \frac{-12}{16} \]The least common denominator (LCD) is: 48.

Rewriting as equivalent fractions with the LCD:\[ = \frac{48}{48}+ \frac{24}{48}+ \frac{36}{48}+ \frac{36}{48}+ \frac{174}{48}+ \frac{-36}{48} \]Rewriting numerators over the common denominator, and changing any addition of negatives to subtraction,\[ = \frac{48 + 24 + 36 + 36 + 174 - 36}{48} \]Totaling the numerator:\[ = \frac{282}{48} \]Reducing the fraction:\[ = \frac{47}{8} \]Dividing by the number of values: 6\[ \frac{47}{8} \div 6 = \frac{47}{8}\times \frac{1}{6}= \frac{47}{48} \]Average of the fractions is:\[ Average = \frac{47}{48} \]