Question

What fraction of 4/7 must be added to itself to make the sum 15/14?

Please tell me help me

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Answer 1

Answer:

we have to find the fraction of

7

4

which must be added to itself to make the sum

14

15

Let x be the fraction of \frac{4}{7}

7

4

⇒ x\times \frac{4}{7}+\frac{4}{7}=\frac{15}{14}x×

7

4

+

7

4

=

14

15

\frac{4}{7}(x+1)=\frac{15}{14}

7

4

(x+1)=

14

15

x+1=\frac{15}{14}\times \frac{7}{4}x+1=

14

15

×

4

7

x=\frac{15}{8}-1=\frac{7}{8}x=

8

15

−1=

8

7

\text{Hence, the fraction is }\frac{7}{8}Hence, the fraction is

8

7

Answer 2

Answer:

To find the fraction of

$\frac{4}{7}$

that must be added to itself to make the sum

$\frac{15}{14}$

Let x be the fraction of

$\frac{4}{7}$

= x × 4/7 +4/7 = 15/14

= 4/7(x+1) = 15/14

= x + 1 = 15/14 × 7/4

= x = 15/8 - 1

= x = 7/8

The fraction is 7/8