Question

what fraction of Nickel as Ni3+ exist in Ni0.98O?​

Answer 1

Answer:

Formula is Ni0.98O1.00

So the ration of Ni : O = 98:100

So if there are 100 atoms of oxygen then 98 atoms of Ni  

Let number of atoms of Ni+2 = x  

Then number of atoms of Ni+3 = 98–x

Charge on Ni = charge on O  

So that oxygen has charge –2

3(98–x) + 2x = 2 (100)

294 –3x +2x = 200  

–x = – 94

x = 94  

Percentage of Ni+2  = (atom of Ni+2/total number of atoms of Ni)100

                                =100(94/98)*100

                                 = 96%

Percentage of Ni+3              

                                 =100 – Ni+2

                                 =100 – 96

                                 = 4 %

                                        Hope, this will help you........