Question

What fraction of wooden craft of density 0.8g/cc will be outside the sea water of density 1.2g/cc? 1 point​

Answer 1

Answer:

You can use trick for this:

∆V(inside) /V = 0.8/1.2

Therefore, ∆V(inside) /V = 2/3

Therefore, ∆V(outside) /V= 1- (⅔) = ⅓

Hopefully you gotta.

Answer 2

Given,

Density of wooden craft=0.8g/cc

Water density outside of the sea water=1.2g/cc

To Find,

Fraction of density.

Solution,

We have the relation for fraction of density of two different surfaces,

So, ∆V(inside) /V = 0.8/1.2

 ⇒ ∆V(inside) /V = 2/3

 ⇒ ∆V(outside) /V= 1- (2/3) = 1/3

Hence, fraction of wooden craft of density 0.8g/cc will be outside the sea water of density 1.2g/cc is 1/3.