Question

What gets printed?
namesl = [‘Amir’, ‘Barry’, ‘Chales’, ‘Dao’]
if ‘amir’ in namesl:
print 1
else:
print 2

Answer 1

print 2..

Chales', 'Dao'] if 'amir' in names1: print(1) else: print(2)

Chales', 'Dao'] if 'amir' in names1: print(1) else: print(2)1

Chales', 'Dao'] if 'amir' in names1: print(1) else: print(2)12 - correct

Chales', 'Dao'] if 'amir' in names1: print(1) else: print(2)12 - correctAn exception is thrown

Chales', 'Dao'] if 'amir' in names1: print(1) else: print(2)12 - correctAn exception is throwndescription: the in keyword can be used to search for a value in a list, set, or dict. In this case the search fails, because the string value is case sensitive.

Answer 2

The output of the given program will be as follows:

namesl = ['Amir', 'Barry', 'Chales', 'Dao']

if "amir" in namesl:

      print ('1')

else:

      print ('2')

Output:

2

• The program checked whether "amir" is present in the list or not.

• In the list capatilized "Amir" is present.

• Therefore, upon checking, instead of printing 1, it printed 2.