Question

What gram of caco3 should be reacted with dilute hcl to produce 66g co2? (ca = 40, c=12, o=16)​

Answer 1

Answer:

Explanation:

Here the reaction will be

CaCO₃+2HCl→CaCl₂+H₂O+CO₂

Here 1 mole of CaCO₃ GIVES 1 MOLE CO₂

Hence 100g CaCO₃ will give 44g CO₂.

Now,

44gCO₂=100gCaCO₃

66gCO₂= $\frac{100}{44}$×66 = 150g.

Hope I helped you.

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Answer 2

Answer:

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Explanation:

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