Question

what happen to the current passing through a conductor, if potential difference across it is doubled and the resistance is halved​

Answer 1

When potential difference is doubled and resistance is halved, then the current flowing is given by

I′=V′R′=2×VR2=4VR=4I0I′=V′R′=2×VR2=4VR=4I0

Hence current will become 4 times the original value.

Answer 2

Let current = I

     voltage = V

     resistance = R

By Ohm's law,

   I = V/R

Now, voltage = 2V

         resistance = R/2

By Ohm's law,

   I' = 2V/R/2

      = 2V * 2/R

      = 4V/R

      = 4I

Therefore, the current passing through the conductor will be quadrupled.