Question

What happen when 1 kg ball fall from the height of 10 m . find kinetic energy?

Answer 1

Assuming g= 9.8m/s^2

m= 1kg

h=10m

u(initial velocity)=0

${v}^{2} = {u}^{2} + 2gh$

${v }^{2} = 0 + 2 \times 9.8 \times 10$

${v}^{2} = 196$

$v = 14 \frac{m}{s}$

$ke = \frac{1}{2} m {v}^{2}$

$= \frac{1}{2} \times 1 \times 196$

$ke = 98j$