English, asked by apple786, 1 year ago

what happened to the flier and the flying machine​ ?class 7 the flying machine ​

Answers

Answered by mahak8744
0

Answer:

i.e. we get

gh = 4/9 g

So acceleration due to gravity at a height R/2 above the surface of the earth is 4/9 times to that on the surface of the earth

So weight at that height will be

Wh = m(4/9g) = 4/9 mg

i.e.

Wh = 4/9 W

So weight will be 4/9 times weight at the surface of the earth

We are given weight on the surface of the earth as

W = 63 N, so we have

Wh = 4/9 × 63N = 28 N

So the weight of the body or gravitational force on it due to the earth at a height equal to half the radius of the earth will be 28 N

Answered by Anonymous
2

Answer:

i.e. we get

gh = 4/9 g

So acceleration due to gravity at a height R/2 above the surface of the earth is 4/9 times to that on the surface of the earth

So weight at that height will be

Wh = m(4/9g) = 4/9 mg

i.e.

Wh = 4/9 W

So weight will be 4/9 times weight at the surface of the earth

We are given weight on the surface of the earth as

W = 63 N, so we have

Wh = 4/9 × 63N = 28 N

So the weight of the body or gravitational force on it due to the earth at a height equal to half the radius of the earth will be 28 N

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