Question

What happened when a solution of potassium chromate is treated with an excess of dilute nitric acid?

Answer 1

Answer:

$Cr_2O_7^{2-} + H_2O$

Explanation:

As we know that when a solution of potassium chromate is reacted or treated with an excess of dilute nitric acid, it produces or releases $Cr_2O_7^{2-} + H_2O$. Therefore, $Cr_2O_7^{2-}$ions and $H_2O$ is formed as a product. So, the resultant product is $Cr_2O_7^{2-} + H_2O$. Here, potassium chromate and dilute nitric acid is is act as a reactant in this chemical reaction. Whereas, $Cr_2O_7^{2-} + H_2O$ acts as a product of this chemical reaction.