what happened when two balls thrown in a vacuum space in same direction so,after how much time they will meet each other and also there are no gravity
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Since the ball takes 12 sec to reach back to its original position, therefore it's total time of travel is 12 sec and time of travel in each direction (up and down) is 6 seconds.
There will be 3 points at which ball has zero velocity
Start pointTop most position, or maximum height reached by ballEnd point (same as starting in case of linear motion and different point in case of parabolic motion)
Question asking that when will ball reach to the same position again where it had been after 5 seconds from start of motion.
This implies that motion is linear motion that's who the ball can retrace its path while traveling downwards.
Since the motion is free of any other external force than the gravity, it will follow the laws of motion simply which means the time it took to reach up is the time taken by it to reach down and, time interval between top point and any point on its path on way up and way down will be same.
This you can find by applying laws of motion.
Therefore time interval between top and position of ball 5 seconds after starting point is
6 - 5 = 1
Therefore it will reach the same point in after the same time interval that is 1 sec
There to reach that point again total time taken by ball is 6(to reach top) + 1(to again reach to that point after reaching top)
Alternate way to do is time taken
Because time taken before that point is equal to the time taken after that point to reach bottom and time taken before is 5sec so after also will be . Therefore time taken to reach that position is total time - time taken after that point.
It's bit or lot confusing way to explain but still i hope you got it ;)
There will be 3 points at which ball has zero velocity
Start pointTop most position, or maximum height reached by ballEnd point (same as starting in case of linear motion and different point in case of parabolic motion)
Question asking that when will ball reach to the same position again where it had been after 5 seconds from start of motion.
This implies that motion is linear motion that's who the ball can retrace its path while traveling downwards.
Since the motion is free of any other external force than the gravity, it will follow the laws of motion simply which means the time it took to reach up is the time taken by it to reach down and, time interval between top point and any point on its path on way up and way down will be same.
This you can find by applying laws of motion.
Therefore time interval between top and position of ball 5 seconds after starting point is
6 - 5 = 1
Therefore it will reach the same point in after the same time interval that is 1 sec
There to reach that point again total time taken by ball is 6(to reach top) + 1(to again reach to that point after reaching top)
Alternate way to do is time taken
Because time taken before that point is equal to the time taken after that point to reach bottom and time taken before is 5sec so after also will be . Therefore time taken to reach that position is total time - time taken after that point.
It's bit or lot confusing way to explain but still i hope you got it ;)
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