Question

what happenes to potential difference, electric field and charge stored if plate distance for a charged isolated capacitor is slowly increased?​

Answer 1

Explanation:

potential difference also increases

Answer 2

Answer:

There can be two cases-

1– Capacitor is charged and then isolated. In this case, charge remains the same as distance between plates increases (conservation of charges). Capacitance value goes down in inverse proportion to distance. Since Q=CV , voltage of capacitor goes up to maintain the same charge. Total energy stored on capacitor remains same.

2– Capacitor remains connected to battery/ DC source. Voltage therefore remains same. Capacitance value goes down in inverse proportion to distance between plates. Correspondingly the charge and also the energy stored gets reduced as excess charge goes back and gets absorbed by battery.