What happens if a lens of refractive index 1.45 is kept in benzene and water which have refractive index of 1.5 and1.0
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animegirl1:
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Refractive index of water = 1.33
Refractive index of benzene = 1.50
Refractive index of benzene with respect to water = Refractive index of water/Refractive index of benzene
= 1.50/1.33
= 150/133
= 1.127
Refractive index of benzene = 1.50
Refractive index of benzene with respect to water = Refractive index of water/Refractive index of benzene
= 1.50/1.33
= 150/133
= 1.127
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