What happens to kinetic energy when mass is doubled n velocity is halved?
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Since,
Kinetic energy = 1/2 x mass x Velocity^2
=> K.E = 1/2 mv^2
But in question it says that When mass is doubled and Velocity is halved.
Then,
Mass = 2m
Velocity = v/2
=> K.E' = 1/2 x 2m x (v/2)^2
=> K.E' = 1/2 x 2m x v^2/4
=> K.E' = mv^2/4
Hence, New Kinetic energy = K.E' = mv^2/4
Kinetic energy = 1/2 x mass x Velocity^2
=> K.E = 1/2 mv^2
But in question it says that When mass is doubled and Velocity is halved.
Then,
Mass = 2m
Velocity = v/2
=> K.E' = 1/2 x 2m x (v/2)^2
=> K.E' = 1/2 x 2m x v^2/4
=> K.E' = mv^2/4
Hence, New Kinetic energy = K.E' = mv^2/4
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