Question

What happens to the area of a rectangle when
(i) its length is doubled, the breadth remaining
the same?
(ii) its breadth is doubled, the length remaining
the same?
(iii) its length and breadth are
both doubled?​

Answer 1

let length of rectangle be l and if it is doubled it becomes 2 L

let breadth of rectangle be b

area of rectangle= length × breadth

2 L × b

2) let length of rectangle be l

let breadth of rectangle be b if breadth is doubled it becomes 2 b

area of rectangle = length× breadth

L× 2 b

3) let length of rectangle be l and if it is doubled it becomes 2 L

let breadth of rectangle be b if breadth is doubled it becomes 2 b

area= length ×breadth

2L × 2b

Answer 2

Answer:

happy Christmas.. see the answer below..

Step-by-step explanation:

Here, let assume that a common rectangle has

length x unit and breadth y unit.

therefore,

i) condition 1 ::---its length is doubled, the breadth remaining the same.

so, length become 2x unit and breadth is y unit

$area \: = \: \: 2x \times y$

$= 2xy \: {unit}^{2}$

II) condition 2 ::---its breadth is doubled, the length remaining the same.

therefore,

so, breadth become 2y unit and length is x unit

$area \: = \: x \times 2y$

$= \: 2xy \: {unit}^{2}$

III) condition 3 ::---its length and breadth are

its length and breadth areboth doubled.

so, length become 2x unit and breadth become 2y unit.

$area \: = \: 2x \times 2y$

$= \: 4xy \: {unit}^{2}$

thanks a lot...