What happens to the area of square
1) When its sides are doubled?
2) When its sides are halved?
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Answer
1) Area of square = side × side = s^2
New side = 2×s
New area = 2s×2s => 4s^2
Area will become four times
2)New side = s/2
New area = s/2×s/2 => s^2/4
Area will become 1/4 times
1) Area of square = side × side = s^2
New side = 2×s
New area = 2s×2s => 4s^2
Area will become four times
2)New side = s/2
New area = s/2×s/2 => s^2/4
Area will become 1/4 times
Answered by
2
we know that :
Area of square = a ×a = a² sq. unit
Case (1st)
if the length of side is halved
=> side of square = a/2
And
Area = (a/2)² = a²/4
that means ...
Area become one by fourth of Area when length of side is halved.
Case (2nd)
if length of side is doubled
=> side = 2a
=> Area of square = (2a)² = 4a²
that means..
Area become 4 times when side of square is doubled.
# hope it helps :)
Area of square = a ×a = a² sq. unit
Case (1st)
if the length of side is halved
=> side of square = a/2
And
Area = (a/2)² = a²/4
that means ...
Area become one by fourth of Area when length of side is halved.
Case (2nd)
if length of side is doubled
=> side = 2a
=> Area of square = (2a)² = 4a²
that means..
Area become 4 times when side of square is doubled.
# hope it helps :)
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