what happens to the area of szuare when (a) sode become 3 times (b) side is halved
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Step-by-step explanation:
let the side be S
so orignal area=S²
so area according to condition 1=(3S)²=9S²
hence it will become 9times of itself.
then area according to condition 2=[S/2]²=S²/4
hence it will become one fourth of itself.
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