Math, asked by Junaod9031, 11 months ago

What happens to the area of the parallelogram, if the base is increased 2 times and height is halved?

Answers

Answered by Anonymous
15

Base of the parallelogram = b

Base of the parallelogram = bHeight of the parallelogram = h

Base of the parallelogram = bHeight of the parallelogram = hArea of the parallelogram = Base * Height

Base of the parallelogram = bHeight of the parallelogram = hArea of the parallelogram = Base * Height = bh sq.units

Base of the parallelogram = bHeight of the parallelogram = hArea of the parallelogram = Base * Height = bh sq.unitsBase is increased 2 times = New Base = 2b

Base of the parallelogram = bHeight of the parallelogram = hArea of the parallelogram = Base * Height = bh sq.unitsBase is increased 2 times = New Base = 2bHeight is halved = New Height = 1/2 * h = h/2

Base of the parallelogram = bHeight of the parallelogram = hArea of the parallelogram = Base * Height = bh sq.unitsBase is increased 2 times = New Base = 2bHeight is halved = New Height = 1/2 * h = h/2New area = Base * Height

Base of the parallelogram = bHeight of the parallelogram = hArea of the parallelogram = Base * Height = bh sq.unitsBase is increased 2 times = New Base = 2bHeight is halved = New Height = 1/2 * h = h/2New area = Base * Height= 2b(h/2)

Base of the parallelogram = bHeight of the parallelogram = hArea of the parallelogram = Base * Height = bh sq.unitsBase is increased 2 times = New Base = 2bHeight is halved = New Height = 1/2 * h = h/2New area = Base * Height= 2b(h/2)=bh sq.units

Base of the parallelogram = bHeight of the parallelogram = hArea of the parallelogram = Base * Height = bh sq.unitsBase is increased 2 times = New Base = 2bHeight is halved = New Height = 1/2 * h = h/2New area = Base * Height= 2b(h/2)=bh sq.unitsNew area = Original area

Base of the parallelogram = bHeight of the parallelogram = hArea of the parallelogram = Base * Height = bh sq.unitsBase is increased 2 times = New Base = 2bHeight is halved = New Height = 1/2 * h = h/2New area = Base * Height= 2b(h/2)=bh sq.unitsNew area = Original areaTherefore the area of the parallelogram remains same, if the increased 2 times and height is halved.

Answered by venkatavr1986
16

Step-by-step explanation:

remains the same

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