Question

What happens to the coulombs force between the 2 charge when a glass is introduced between the two charges​

Answer 1

Answer:

It reduces

Explanation:

Recall F = 1/ 4πe0; now when a glass sheet is introduced; then  new value of Force F' = 1/4pie0er ; ie F/er ; which er- dielectric constant;

now Er > 1 ; Hence F'<F.