What happens to the focus of a concave lens (glass μ = 1.5) of focal length 20 cm (in air) when dipped in
(a) water of μ =1.33
(b) oil of μ = 1.8
Support your answer with a relevant ray diagram.
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Answer:
focal length f = R/2(μg - μw)
f = 40/2(1.5 - 1.3)
f = 20/0.2
f = 100 cm
and in the second part
f = 40/2(1.5 - 1.8)
f = 20/(-0.3)
f = -66.6
as the refractive index of the medium is greater than the refractive index of glass therefore the nature of the glass will change and now it behave as diverging lens
hope this helps love
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