what happens to the K.E. of the body if it's velocity is doubled
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Answered by
2
Kinetic energy = (mv^2)/2(mv^2)/2
Where we have taken v as velocity.
If we replace v with 2v, we have:
Kinetic energy (new) = m(2v)^2/2m(2v)^2/2 = 4(mv^2)/24(mv^2)/2
So, as you can see yourself, that the new kinetic energy is four times than the general value of kinetic energy we had found above. So, it is simply quadrupled on doubling the velocity.
Thus the final answer is it becomes 4 times and increases.
Please mark my answer as the brainliest.
Where we have taken v as velocity.
If we replace v with 2v, we have:
Kinetic energy (new) = m(2v)^2/2m(2v)^2/2 = 4(mv^2)/24(mv^2)/2
So, as you can see yourself, that the new kinetic energy is four times than the general value of kinetic energy we had found above. So, it is simply quadrupled on doubling the velocity.
Thus the final answer is it becomes 4 times and increases.
Please mark my answer as the brainliest.
abs2001:
I hope it helped you
Answered by
1
Hyy....
Since, K E == 1/2 M (V)^2
K E is directly proportional to square of velocity
Now, if velocity is doubled then the K E will be quadrupled
BRAINLIEST PLEASE
(^_^)
Since, K E == 1/2 M (V)^2
K E is directly proportional to square of velocity
Now, if velocity is doubled then the K E will be quadrupled
BRAINLIEST PLEASE
(^_^)
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