What happens to the kinetic energy when that mass of the body is doubled but the velocity is reduced to half
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KE gets half.!!!!!!!!!!!!!!
Answered by
2
Initially:
let mass=m1
Kinetic energy =KE1
velocity=v1
KE1=1/2*m1*v1^2
Given: m2=2m1
v2=1/2v1
So:-
KE2=1/2*m2*v2^2
=1/2*2m1*1/4v1^2
=1/4m1*v1^2
So KE2/KE1
=1/4m1v1^2/1/2m1v1^2
=1/2
So the kinetic energy becomes half of the initial kinetic energy.
Thanks.
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