Question

what happens to the pressure when the volume of a gas doubled at gas constant temperature​

Answer 1

Explanation:

Boyle's law describes the relationship between pressure (P) and volume (V) of a gas at constant temperature (T), PV = constant at constant temperature. ... When volume increases, pressure decreases.

Answer 2

When the volume of a gas doubled at gas constant temperature​, then the pressure gets halved.

Boyle's Pressure-volume Law definition:

• At constant temperature, the pressure of a given quantity of gas varies inversely with the volume of the gas.
• $P_1V_1=P_2V_2$    (at constant Temperature T)

Given:

• $P_1=P$  (initial pressure )
• $V_1=V$  (initial volume)
• $V_2=2V$  (final volume)

To be Found:

the value of $P_2$ (the final pressure of the gas)

Formula used:

We can substitute the values of $P_1, V_1, V_2$  in the expression of the Boyle's law,

We get, $P_1V_1=P_2V_2$

⇒$PV= P_2 * (2V)$

We can now find the value of $P_2$ by simplifying the given equation,

⇒$P_2=\frac{P*V}{2V} = \frac{P}{2}$

Since the value of $P_2$ has become $P/2$, we can say that pressure has become half of initial value.

So, when the volume of a gas doubled at gas constant temperature​, then the pressure gets halved.