What happens to the time period of a simple pendulum when it is taken from equator to the pole?
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g at pole is greater than the g at equator because radius of equator is 21km greater than the radius of pole
T=2π√l/g
g increases while moving from equator to pole
So time period of simple pendulum decreases
Answered by
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From the formula,
Time period of a simple pendulum
=2π√(l/g)
We know that Time Period is inversely proportional to acceleration due to gravity
From the chapter GRAVITATION,
We know that Gravitational Force is stronger at the poles than at the equator so the value of g is greater at the poles than at the equator.
So, The time period of the simple pendulum DECREASES as we go FROM Equator TO the Poles.
The above reason is also the answer to why the equator is bulged out causing the shape of the Earth to be OBLATE
Time period of a simple pendulum
=2π√(l/g)
We know that Time Period is inversely proportional to acceleration due to gravity
From the chapter GRAVITATION,
We know that Gravitational Force is stronger at the poles than at the equator so the value of g is greater at the poles than at the equator.
So, The time period of the simple pendulum DECREASES as we go FROM Equator TO the Poles.
The above reason is also the answer to why the equator is bulged out causing the shape of the Earth to be OBLATE
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