Physics, asked by rajaumerrathore09, 23 days ago

What happens to total radiation from a black body if it’s absolute temperature is doubled?

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Answered by diyabhana

Answer:

If the absolute temperature of a black body is doubled the percentage increase in the rate of loss of heat by radiation is . P2-P1P1×100=[(T2T1)4-1]×100 . Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

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