What happens when
(1) bromoethane is treated with zinc and hydrochloric acid
(ii) hydrogen is passed into 2-bromopropane in the
presence of palladium?
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Explanation:
(1) when bromoethane is treated with zinc and hydrochloric acid
= It is a single replacement reaction where zinc metal displaces the hydrogen to form hydrogen gas and zinc chloride, a salt. Zinc reacts quickly with the acid to form bubbles of hydrogen. "Generally, when an "alkyl halide" is treated with "zinc" and "hydrochloric acid", it is "reduced" to the "respective alkane"
(ii) hydrogen is passed into 2-bromopropane in the
to from propane.
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