What happens when 1)dilute sulphuric acid is poured over copper plate 2)iron nail are placed in copper sulphate solution
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1) When dilute sulphuric acid is poured on a copper plate, bubbles appear on the surface of plate. This happens because sulphuric acid reacts with copper to produce hydrogen gas. This can be shown by following equation:
Sulphuric acid + Copper → Copper sulphate + Hydrogen gas
2) When Iron nail (Ferrum) is dipped in Copper sulphate (CuSO4) solution, copper sulphate changes its color from blue to light green. This shows Iron is more reactive than Copper, it can replace Copper from CuSO4. CuSO4 is in blue Color and FeSO4 is in light green color.
Sulphuric acid + Copper → Copper sulphate + Hydrogen gas
2) When Iron nail (Ferrum) is dipped in Copper sulphate (CuSO4) solution, copper sulphate changes its color from blue to light green. This shows Iron is more reactive than Copper, it can replace Copper from CuSO4. CuSO4 is in blue Color and FeSO4 is in light green color.
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