What happens when 2-bromopentane is treated with alcoholic KOH
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Answer:
Butene is formed when 2-bromopentane is treated with potassium hydroxide (KOH).
Explanation:
The reaction or treatment of 2-bromopentane with alcoholic KOH is known as dehydro halogenation reaction.
The reaction is named so because hydrogen and halogen atom (bromine) is removed to form double bond carbon atom that butene .
CH_{3}-CHBr-CH_{2}-CH_{3} + KOH \rightarrow CH_{2}=CH-CH_{2}-CH_{3}
Answered by
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KOH
CH3 CH2 CH2 CH(Br)CH3 + ——>
(alc. )
CH3CH2CH=CH CH3.
Explanation:
the reaction is known as β-elimination and the major product is pent-2-ene according to saytzeff's rule.
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