Question

What happens when 2-bromopropane is treated with alcoholic KOH ?

Answer 1

propane and KBr is formed as product

Answer 2

When 2-bromopropane is treated with alcoholic KOH it leads to the evolution of propene gas.

Explanation:

• To find out the product formed during the chemical reaction, the chemical formula of reactants involved in the reaction must be identified.
• In the given word equation of the reactants, the compound involved as reactants are as follows:

1. 2-bromopropane
2. Alcoholic KOH

• When 2-bromopropane is treated with alcoholic KOH, it leads to the formation of the following product:

1. Propene gas
2. Sodium bromide
3. Water.

• The reaction requires the conversion of alkane to an alkene. The chemical equation involved in the reaction is as follows:

$CH_3CHCH_3Br+KOH\rightarrow CH_2CHCH_3+NaBr+H_2O$

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