what happens when 2- butyne is reduced with Pd/BaSO4
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It is used for the hydrogenation of alkynes to cis alkenes (i.e. without further reduction into alkanes) When the triple bond is (2-butyne) hydrogenated over the Lindlar's catalyst i.e.Pd/BaSO4 it gives predominantly cis alkene(2-butene).
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When 2- butyne is reduced with Pd/BaSO₄, 2-butene is formed with cis configuration.
- The reaction that is happening here is hydrogenation.
- In hydrogenation, hydrogens are get added and the double or triple bonds get broken.
- The catalyst here used is Lindlar's catalyst, which is Pd/BaSO₄.
- When this catalyst is used, 2- butyne which is an alkyne, gets converted to 2- butene.
- But the main thing is, it gives the cis type of configuration.
- The cis refers to the large molecular size groups to be on a similar side from the double, triple, or single bond.
- One bond of triple bond breaks and 2 hydrogens are added with each electron.
- Na/NH₃ will give trans formation.
- Thus the correct answer is cis 2-butene.
To know more about hydrogenation and Lindlar's catalyst:
What is hydrogenation? Write its industrial application?
https://brainly.in/question/1124024?msp_srt_exp=5
Write the reaction of 2-butyne with Lindlar catalyst.
https://brainly.in/question/8921915?msp_srt_exp=5
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