Science, asked by aman746726, 5 months ago

what happens when 2- butyne is reduced with Pd/BaSO4​

Answers

Answered by rahul42291
0

Answer:

It is used for the hydrogenation of alkynes to cis alkenes (i.e. without further reduction into alkanes) When the triple bond is (2-butyne) hydrogenated over the Lindlar's catalyst i.e.Pd/BaSO4 it gives predominantly cis alkene(2-butene).

Answered by UsmanSant
0

When 2- butyne is reduced with Pd/BaSO₄, 2-butene is formed with cis configuration.

  • The reaction that is happening here is hydrogenation.
  • In hydrogenation, hydrogens are get added and the double or triple bonds get broken.
  • The catalyst here used is Lindlar's catalyst, which is Pd/BaSO₄.
  • When this catalyst is used, 2- butyne which is an alkyne, gets converted to 2- butene.
  • But the main thing is, it gives the cis type of configuration.
  • The cis refers to the large molecular size groups to be on a similar side from the double, triple, or single bond.
  • One bond of triple bond breaks and 2 hydrogens are added with each electron.
  • Na/NH₃ will give trans formation.
  • Thus the correct answer is cis 2-butene.

To know more about hydrogenation and Lindlar's catalyst:

What is hydrogenation? Write its industrial application?

https://brainly.in/question/1124024?msp_srt_exp=5

Write the reaction of 2-butyne with Lindlar catalyst.

https://brainly.in/question/8921915?msp_srt_exp=5

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