Chemistry, asked by vennelaboddeti3528, 1 year ago

What happens when

(a) Borax is heated strongly,

(b) Boric acid is added to water,

(c) Aluminium is treated with dilute NaOH,

(d) BF 3 is reacted with ammonia?

Answers

Answered by hrishikesh8
49
1.when borax is heated strongly it first form sodium metaborate then further reduce to form boric anhydride.
2.when boric acid is added to water then it accepts electron from -OH ion
3.when aluminum is treated with NaOH it forms sodium tetrahydroxoaluminate
4.when BF3 is reacted with ammonia B occupies it's octate by sharing with lone pairs of NH3
Answered by Anonymous
24
__________Heya !!____________
===============================

=================================
___Your answer is in Attachment !!___
=================================

==============
=================================

_______Have a look at that_________

==================================
==============

_________Hope it helps__________
==================================

Be_Brainly
==========
==================================
Attachments:
Similar questions