Question

What happens when

(a) Dilute sulphuric acid is poured on a copper plate?

(b) Iron nails are placed in a copper sulphate solution?

Write word equations of the reactions involved.​

Answer 1

Answer:

(A) no reaction

Explanation:

in first question no reaction will take place as copper reacts with concentrated sulphuric acid to form hydrogen

• (B)Iron in copper sulphate gives rise to iron sulphate and copper is evolved

Answer 2

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I hope You understand this

Answer:

(i) No reaction occurs when dilute sulphuric acid is poured on a copper plate. However, when concentrated sulphuric acid is poured on a copper plate, hydrogen gas evolves along with the formation of blue coloured copper sulphate crystals. The chemical reaction for the reaction between concentrated sulfuric acid and copper is:

 $Cu + H_{2}SO_{4} (conc.)$  → $CuSO_{4} + H_{2}$

ii) Iron being more reactive displaces copper from copper sulphate. In this reaction, the blue colour of copper sulphate fades and there is a deposition of copper on the iron nail.

$Fe + CuSO_{4}$ →  $FeSO_{4} + Cu$