Question

What happens when a mixture of copper oxide and copper sulphide is heated?

Answer 1

Answer:

Double replacement reaction occurs when a mixture of copper(II) oxide and Copper (II) sulphide is heated. In the above reaction, S and O are replaced from their respective compounds and Cu is formed. If copper(I) oxide is heated with copper(I) sulphide, then no reaction would occur.

Explanation:

Answer 2

When a mixture of copper oxide and copper sulphide is heated then pure copper is obtained along with sulfur dioxide.

Explanation:

A mixture of copper oxide and copper sulphide is used to extract pure copper. During this process, in the chalcopyrite copper (II) ions are reduced to copper(I) sulfide which is further reduced to copper metal at the final stage.

The reaction equation for obtaining copper sulphide from chalcopyrite is as follows.

   $2CuFeS_{2} + 2SiO_{2} + 4O_{2} \rightarrow Cu_{2}S + 2FeSiO_{3} + 3SO_{2}$

And, with the final blast of air copper(I) sulfide is converted into copper as follows.

        $Cu_{2}S + O_{2} \rightarrow 2Cu + SO_{2}$

Therefore, when a mixture of copper oxide and copper sulphide is heated the the reaction equation is as follows.

      $2Cu_{2}O + Cu_{2}S \rightarrow 6Cu + SO_{2}$

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