Question

What happens when chlorine is passed into solution of sulphur (iv)oxide in water

Answer 1

sulphur( iv) oxide means sulphur dioxide.. so2+cl2+H2o gives H2so4+Hcl..

Answer 2

Answer: It leads to the formation of sulfuric acid and hydrochloric acid.

Explanation:

When sulfur (IV) oxide or sulfur dioxide is passed on with chlorine gas, mixture of acids are formed.

The reaction between the two is given by the equation:

$SO_2(g)+Cl_2(g)+2H_2O(l)\rightarrow H_2SO_4(aq.)+2HCl(aq.)$

By Stoichiometry of the reaction:

1 mole of sulfur dioxide reacts with 1 mole of chlorine gas and 2 moles of water to produce 1 mole of sulfuric acid and 2 moles of hydrochloric acid.

Hence, the reaction between the two leads to the formation of sulfuric acid and hydrochloric acid.