Question

what happens when ethanol is warmed with ethanoic acid in the presence of concentrated sulphuric acid write the balanced chemical equation

Answer 1

when ethanol is warmed with ethanoic acid in the presence of concentrated sulphuric acid then the following reaction takes place :-
C2H5OH (Ethanol) + CH3COOH (Ethanoic acid) ----->CH3COOC2H5 (Ethyl acetate) + H2O (Water)

Answer 2

Reaction of ethanol and ethanoic acid in the presence of concentrated sulfuric acid.

• The reactants given are as follows:

1. Ethanol - $C_2H_5OH$
2. Ethanoic acid - $CH_3COOH$

• The reactants are heated in the presence of concentrated sulfuric acid ($H_2SO_4$) as catalyst.
• As a result of reaction between the reactant double displacement and dehydrogenation reaction occurs.
• This leads to formation of ethylethonate and water as the product end product of the reaction.
• The balanced chemical equation involved in the reaction are as follows:

$C_{2} H_{5} O H+C H_{3} C O O H \stackrel{C o n c . H_{2} S O_{4}}{\longrightarrow} C H_{3} C O O C_{2} H_{5}+H_2O$

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